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Math Help - derivative question

  1. #1
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    derivative question

    how do i get the derivative of

    f(T) = sqrt(6)/t^4
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  2. #2
    MHF Contributor
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    f(t) = sqrt(6)/t^4
    f(t) = sqrt(6) *[t^(-4)]
    f'(t) = sqrt(6)*[(-4)*t^(-5)]
    f'(t) = -4*sqrt(6) *[t^(-5)]
    f'(t) = -4sqrt(6) / t^5

    That is it.
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  3. #3
    MHF Contributor
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    But more importantly, how do you get this answer?

    f(t)=\frac{\sqrt{6}}{t^4}

    The squareroot of 6 is a constant, so you can bring just multiply that constant to the answer at the end.

    Now you have this: \sqrt{6}t^{-4}

    From here, it's a simple power rule problem.
    Last edited by Jameson; October 26th 2005 at 06:09 PM.
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