# Math Help - derivative question

1. ## derivative question

how do i get the derivative of

f(T) = sqrt(6)/t^4

2. f(t) = sqrt(6)/t^4
f(t) = sqrt(6) *[t^(-4)]
f'(t) = sqrt(6)*[(-4)*t^(-5)]
f'(t) = -4*sqrt(6) *[t^(-5)]
f'(t) = -4sqrt(6) / t^5

That is it.

3. But more importantly, how do you get this answer?

$f(t)=\frac{\sqrt{6}}{t^4}$

The squareroot of 6 is a constant, so you can bring just multiply that constant to the answer at the end.

Now you have this: $\sqrt{6}t^{-4}$

From here, it's a simple power rule problem.