how do i get the derivative of

f(T) = sqrt(6)/t^4

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- Oct 12th 2005, 04:26 PMkimchilandderivative question
how do i get the derivative of

f(T) = sqrt(6)/t^4 - Oct 12th 2005, 10:12 PMticbol
f(t) = sqrt(6)/t^4

f(t) = sqrt(6) *[t^(-4)]

f'(t) = sqrt(6)*[(-4)*t^(-5)]

f'(t) = -4*sqrt(6) *[t^(-5)]

f'(t) = -4sqrt(6) / t^5

That is it. - Oct 26th 2005, 06:01 PMJameson
But more importantly, how do you get this answer?

$\displaystyle f(t)=\frac{\sqrt{6}}{t^4}$

The squareroot of 6 is a constant, so you can bring just multiply that constant to the answer at the end.

Now you have this: $\displaystyle \sqrt{6}t^{-4}$

From here, it's a simple power rule problem.