Anyone know what the derivative of cos(sinx) is? Thanks.
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Originally Posted by ctran Anyone know what the derivative of cos(sinx) is? Thanks. Use the chain rule: $\displaystyle \frac{d}{dx} f(g(x))=f'(g(x))g'(x)$ with $\displaystyle g(x)=\sin(x)$ and $\displaystyle f(x)=\cos(x)$ CB
Originally Posted by ctran Anyone know what the derivative of cos(sinx) is? Thanks. let $\displaystyle y=cos(sinx)$ $\displaystyle \frac{dy}{dx}=-sin(sinx).cosx$
I'm sure glad you guys got in before me. I would have answered, "Yes!"
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