A global min is a point where the y-value is the least of all possible y-values in the range of the function. No other output will be less.
I know how to solve for local min and max.
F = 2x^2 + y^2 +4x -4y +5
The point (-1,2) is a local minimum, but my book also points out that it is a global minimum.
Can anyone tell me how to find the global max/min after I have found critical points and local max/min.
So what you need to do, to prove a global minimum, is show that it's the smallest of the local minima, and that the curve does not go off to .
Yes I know you weren't told to prove that it is a global minimum, consider this post a "for information" one.