Alternatively, you can set the independent variable to and integrate from to .
Edit: You'd multiply it by to get both sides' worth.
I have been trying to find the archlength of , where 0 ≤ x ≤ 2.
I first solved .
Then I solved for y'.
.
The formula I have to find arclength is .
So I plugged in and got this:
.
I evaluated , because my book offers a formula for the form .
The formula was
My and my , so I plugged those into the formula.
What I got out was this:
This is what I got to. Now, I need to evaluate it from 0 to 2. But when I plug in 2 for the value of x, my answer is undefined. Did I do something wrong? Is there a different way to do this? Please...PLEASE help!
http://www.wolframalpha.com/input/?i...1%2B(1/x))^0.5
click on 'Show Steps'
I hope it helps.