Results 1 to 2 of 2

Math Help - Evaluate the limit using the squeeze theorem?

  1. #1
    Newbie
    Joined
    Oct 2009
    Posts
    11

    Evaluate the limit using the squeeze theorem?



    lim (x-->0) xe^cos(pi/x)


    any help is appreciated!
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Super Member Deadstar's Avatar
    Joined
    Oct 2007
    Posts
    722
    I'm not 100% sure if this is right but this is certainly what I would do...
    Since -1 \leq \cos(\pi/x) \leq 1 we have...

    x e^{-1} \leq x e^{\cos(\pi/x)} \leq x e^1.

    So taking limits as x->0 we get...

    0 \leq x e^{\cos(\pi/x)} \leq 0.

    So by the squeeze theorem. \lim_{x \rightarrow 0} e^{\cos(\pi/x)} = 0.

    Think that's right but hopefully someone will drop by to confirm.
    I also checked the limit with MAPLE and it came out to be 0 as well.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Need help with example of Squeeze Theorem
    Posted in the Calculus Forum
    Replies: 2
    Last Post: September 26th 2009, 05:03 AM
  2. Squeeze Theorem
    Posted in the Calculus Forum
    Replies: 3
    Last Post: September 20th 2009, 12:21 AM
  3. squeeze theorem
    Posted in the Calculus Forum
    Replies: 7
    Last Post: April 22nd 2009, 03:49 AM
  4. Using the Squeeze Theorem to find a limit.
    Posted in the Calculus Forum
    Replies: 1
    Last Post: October 28th 2008, 12:14 AM
  5. Squeeze Theorem
    Posted in the Calculus Forum
    Replies: 1
    Last Post: December 13th 2005, 06:16 PM

Search Tags


/mathhelpforum @mathhelpforum