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Math Help - Vector calculus

  1. #1
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    Oct 2009
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    Vector calculus

    can anyone tell me how

     \epsilon \nabla \left(\frac{1}{\epsilon}\right)

    becomes

    - \ln  (\nabla \epsilon)

    where \epsilon can be a function of position, \epsilon (r)
    Last edited by facetten; October 16th 2009 at 02:50 PM.
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  2. #2
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    Oct 2009
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    nvm, sorry for your time. just use the identities

     \nabla \ln  ( \epsilon) =  \left(\frac{1}{\epsilon}\right) \nabla \epsilon
     \nabla  \left(\frac{1}{\epsilon}\right) =  (-1/ \epsilon^2) \nabla \epsilon
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