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Math Help - integration

  1. #1
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    integration

    dv=cos5xdx ==> v= \frac 1{5} sin5x

    can someone show me how to get that?
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by jeph View Post
    dv=cos5xdx ==> v= \frac 1{5} sin5x

    can someone show me how to get that?
    First you should notice that what you have is:

    \frac{dv}{dx}= \cos(5\,x)

    Now the function whose derivative is \cos is \sin, so we try w(x)=\sin(5\,x) differentiating we find the derivative is 5\,\cos(5\,x), so we need:

    v=\frac{1}{5} \sin(5\,x)

    RonL
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