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Math Help - help with a tough integration

  1. #1
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    help with a tough integration

    i need help solving this integral to use it in a physics problem.

    \int(dx/(10.2-x)^2)
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    Quote Originally Posted by Chadly724 View Post
    i need help solving this integral to use it in a physics problem.

    \int(dx/(10.2-x)^2)
    Let y = 10.2 - x ==> dy = -dx

    So
    \int \frac{dx}{(10.2-x)^2} = \int \frac{-dy}{y^2} = \frac{1}{y} + C = \frac{1}{10.2 - x} + C

    -Dan
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