# help with a tough integration

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• Jan 29th 2007, 07:34 PM
Chadly724
help with a tough integration
i need help solving this integral to use it in a physics problem.

$\int(dx/(10.2-x)^2)$
• Jan 29th 2007, 07:51 PM
topsquark
Quote:

Originally Posted by Chadly724
i need help solving this integral to use it in a physics problem.

$\int(dx/(10.2-x)^2)$

Let $y = 10.2 - x$ ==> $dy = -dx$

So
$\int \frac{dx}{(10.2-x)^2} = \int \frac{-dy}{y^2} = \frac{1}{y} + C = \frac{1}{10.2 - x} + C$

-Dan