Show that $\displaystyle \int \frac{x}{\sqrt{x^2-4}}dx=\sqrt{x^2-4}+c$ Hence find the exact value of $\displaystyle \int_{\sqrt{5}}^{\sqrt{8}}\frac{\ln (x^2-4)}{\sqrt{x^4-4}}dx$ I could do the first part but no idea about the 2nd part.
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