hey guys i know this sounds like an easy question but isn't the domain of x^2+7 (-infinity,infinity)?
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Originally Posted by Asuhuman18 hey guys i know this sounds like an easy question but isn't the domain of x^2+7 (-infinity,infinity)? Yes. But if you want to find an inverse function of this function then this domain will need to be restricted to make the function 1-to-1.
no this is the inverse function. the normal funtion was y=sqrt(x-7). I am pretty sure this is right but my online hw is rejecting it
Originally Posted by Asuhuman18 no this is the inverse function. the normal funtion was y=sqrt(x-7). I am pretty sure this is right but my online hw is rejecting it Well then, the inverse relation will be $\displaystyle y = {\color{red}\pm} \sqrt{x - 7}$.
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