• Jan 29th 2007, 05:02 PM
bjorgen
Hi all, just signed up, wondering if anyone could look at a problem on a practice midterm of mine and explain why the limit is 1 and not 0

the midterm is here http://www.math.washington.edu/~m124...1_pevtsova.pdf

edit, needed help with 1 b
• Jan 29th 2007, 05:07 PM
ThePerfectHacker
Factor,
$\lim_{x\to 0} \frac{x^2-2x+1}{x-1}$
Factor,
$\lim_{x\to 0}\frac{(x-1)(x-1)}{x-1}$
Thus,
$\lim_{x\to 0}(x-1)=-1$
• Jan 29th 2007, 06:52 PM
bjorgen
thanks, but doesn't the problem read x --> 1? in that case you'd do 1-1 meaning the limit would be 0?
• Jan 29th 2007, 07:10 PM
ThePerfectHacker
Quote:

Originally Posted by bjorgen
thanks, but doesn't the problem read x --> 1? in that case you'd do 1-1 meaning the limit would be 0?

Yes
• Jan 29th 2007, 07:13 PM
bjorgen
thanks, but the answer page says that it's one, must be an error?