Sorry I don't know how to write a nice looking equation on here so, this is the question:
rho^2 (sin^(2) (phi) * sin^(2) (theta) + cos^(2) (phi)) = 9
What surface is this?
Are you away that, to convert from spherical to cartesian coordinates, you use the following:
$\displaystyle x = \rho \cos(\phi) \sin(\theta) $
$\displaystyle y = \rho \sin(\phi) \sin(\theta) $
$\displaystyle z = \rho \cos(\theta)$
Some of these bear striking resemblance to your equation, and that might help you to proceed.