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Math Help - equation of the tangent line

  1. #1
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    equation of the tangent line

    Find the equation of the tangent line to the following curve at the given point P. Illustrate by graphing the curve and the tangent line on the same screen.


    1


    what did I do wrong? please help!

    Here are the steps:
    I did it according to this Find the equation of the tangent line to the following curve at the given point P. ? - Yahoo! Answers

    y`=6-2x^(1/2)
    6-2(1)^(1/2)
    y`=4


    y-4=4(x-1)
    y-4=4x-4

    y`=4x (and it's WRONG T_T)

    please help me thanks you!!!
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  2. #2
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    Quote Originally Posted by greenbee View Post
    Find the equation of the tangent line to the following curve at the given point P. Illustrate by graphing the curve and the tangent line on the same screen.


    1


    what did I do wrong? please help!

    Here are the steps:
    I did it according to this Find the equation of the tangent line to the following curve at the given point P. ? - Yahoo! Answers

    y`=6-2x^(1/2)
    6-2(1)^(1/2)
    y`=4


    y-4=4(x-1)
    y-4=4x-4

    y`=4x (and it's WRONG T_T)

    please help me thanks you!!!
    your derivative is incorrect ...

    y = 6x - 2\sqrt{x}

    y' = 6 - \frac{1}{\sqrt{x}}
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  3. #3
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    Quote Originally Posted by skeeter View Post
    your derivative is incorrect ...

    y = 6x - 2\sqrt{x}

    y' = 6 - \frac{1}{\sqrt{x}}
    how do i make the equation including the points?
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  4. #4
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    Quote Originally Posted by greenbee View Post
    how do i make the equation including the points?
    use the point-slope form of a linear equation ...

    y - y_1 = m(x - x_1)

    where (x_1,y_1) is your point, and the slope is m = f'(x_1)
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  5. #5
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    Quote Originally Posted by skeeter View Post
    use the point-slope form of a linear equation ...

    y - y_1 = m(x - x_1)

    where (x_1,y_1) is your point, and the slope is m = f'(x_1)
    thank you!!!
    Follow Math Help Forum on Facebook and Google+

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