..."Find the point(s) on the parabola at which the normal line passes through the point (2,0). Illustrate by graphing the parabola and the normal line(s)."
I started off by finding which would be the slope of a tangent line at x.
Next, I assumed the negative reciprocal is the slope of the normal line.
*** Here's the problem: the tangent line's slope is simply 2, so its reciprocal is only -1/2 and not all the mess you wrote!
Remember: slope is a number.
Then, using the given point:
But when I use the quadratic formula I get:
which appears to be a problem. I must have messed up somewhere...
Any help with solving this problem is appreciated.