Help me study for my test tomorrow!

Tomorrow's my test and there are a few concepts that I have to work on.

1. Sketch the region bounded by the graphs of the equations, and determine its area.

$\displaystyle y=\frac{4}{\sqrt x}$

$\displaystyle y=0, x=1, x=9$

Answer: A=16

My main problem with this is getting rid of the $\displaystyle \sqrt x$ from under so I can begin to integrate.

2. Find the particular solution of the differential equation $\displaystyle f''(x)=6(x-1)$ whose graph passes through the point (2,1) and is tangent to the line $\displaystyle 3x-y-5=0$ at that point.

I already found that $\displaystyle f'(x)=3x^2-6x$ and $\displaystyle f(x)=x^3-3x^2$. What now? I don't get what the question is asking me.

3. Use the Second Fundamental Theorem of Calculus to find $\displaystyle F'(x)$.

F(x)=(integration sign, x between 0 and x)$\displaystyle t^2\sqrt {1+t^3} dt$

Answer=$\displaystyle x^2+3x+2$

I know that $\displaystyle F(x)$ is the antiderivative of the inside of the integration symbol, but I don't understand how to find $\displaystyle F'(x)$.

Some help on these questions would greatly be appreciated.