Finding the derivative
Hi guys...I'm having some troubles with this one question and it's really starting to bug me cause I keep getting it wrong.
The question is:
So, I tried simplifying it...
v = (9*x^1/2 + 5/(3*x^1/3))^2
v = (9x^1/2 + 5/(3x^1/3))^2
I then distributed the 2 from outside the brackets into the brackets, so:
v = (81x + 25/9x^2/3)
Then I took the derivative...
v(der) = 81 + 25/6x^-1/3
Should I have done something with the 25 on the top of that fraction? I'm really not sure.
Thanks in advance.
if you're trying to find , just use the chain rule. expanding that binomial is just going to make a bigger mess.
Originally Posted by dark-ryder341
I really doubt you're expected to have to multiply that out. So just use the chain rule as the previous poster suggested.
n(a + b)^n-1*(da/dx + db/dx)