v = (9*x^1/2 + 5/(3*x^1/3))^2
v = (9x^1/2 + 5/(3x^1/3))^2
I then distributed the 2 from outside the brackets into the brackets, so:
v = (81x + 25/9x^2/3)
Then I took the derivative...
v(der) = 81 + 25/6x^-1/3
Should I have done something with the 25 on the top of that fraction? I'm really not sure.
Thanks in advance.
Oct 14th 2009, 04:33 PM
Originally Posted by dark-ryder341
Hi guys...I'm having some troubles with this one question and it's really starting to bug me cause I keep getting it wrong.