Tangent line to curve

**dymondahlis** · October 14th 2009, 03:00 PM

How to find the tangent line to the curve g(t) = (t + 1, t^2 + 1, t^3 + 1)
at the point (0, 2, 0)?

**redsoxfan325** · October 14th 2009, 03:45 PM

Originally Posted by dymondahlis

How to find the tangent line to the curve g(t) = (t + 1, t^2 + 1, t^3 + 1)
at the point (0, 2, 0)?

This probably belongs in the Calculus forum.

$g'(t)=(1,2t,3t^2)$

The value of $t$ that yields $g(t)=(0,2,0)$ is $t=-1$ .

So evaluating $g'(-1)$ ...

**dymondahlis** · October 14th 2009, 04:43 PM

Originally Posted by redsoxfan325

This probably belongs in the Calculus forum.

$g'(t)=(1,2t,3t^2)$

The value of $t$ that yields $g(t)=(0,2,0)$ is $t=-1$ .

So evaluating $g'(-1)$ ...

Thanks alot!!!

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