Originally Posted by
redsoxfan325 This probably belongs in the Calculus forum.
$\displaystyle g'(t)=(1,2t,3t^2)$
The value of $\displaystyle t$ that yields $\displaystyle g(t)=(0,2,0)$ is $\displaystyle t=-1$.
So evaluating $\displaystyle g'(-1)$ ...