# Tangent line to curve

• October 14th 2009, 03:00 PM
dymondahlis
Tangent line to curve
How to find the tangent line to the curve g(t) = (t + 1, t^2 + 1, t^3 + 1)
at the point (0, 2, 0)?
• October 14th 2009, 03:45 PM
redsoxfan325
Quote:

Originally Posted by dymondahlis
How to find the tangent line to the curve g(t) = (t + 1, t^2 + 1, t^3 + 1)
at the point (0, 2, 0)?

This probably belongs in the Calculus forum.

$g'(t)=(1,2t,3t^2)$

The value of $t$ that yields $g(t)=(0,2,0)$ is $t=-1$.

So evaluating $g'(-1)$ ...
• October 14th 2009, 04:43 PM
dymondahlis
Quote:

Originally Posted by redsoxfan325
This probably belongs in the Calculus forum.

$g'(t)=(1,2t,3t^2)$

The value of $t$ that yields $g(t)=(0,2,0)$ is $t=-1$.

So evaluating $g'(-1)$ ...

Thanks alot!!!