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Thread: Find the coordinates of the turning point

  1. October 13th 2009, 11:21 PM #1
    mastermin346
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    Find the coordinates of the turning point

    how can i find the coordinates of the turning point 4x(x-1)(x-2)?anyone can help.
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  2. October 13th 2009, 11:35 PM #2
    alexmahone
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    Quote Originally Posted by mastermin346 View Post
    how can i find the coordinates of the turning point 4x(x-1)(x-2)?anyone can help.
    y=4x(x-1)(x-2)=4(x^3-3x^2+2x)

    \frac{dy}{dx}=4(3x^2-6x+2)

    At the turning point, \frac{dy}{dx}=0

    x=1\pm{\frac{1}{\sqrt{3}}}
    Last edited by alexmahone; October 13th 2009 at 11:46 PM.
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  3. October 13th 2009, 11:47 PM #3
    mastermin346
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    thank you
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