[the integral of] (4/t^2)i + (te^t)j + 5t*[the square root of](t)k
Follow Math Help Forum on Facebook and Google+
Originally Posted by cottekr [the integral of] (4/t^2)i + (te^t)j + 5t*[the square root of](t)k Again, do componentwise integration: $\displaystyle \int\frac{4}{t^2}\,dt=\int 4t^{-2}\,dt=\dots$ $\displaystyle \int te^t\,dt$ -- Use integration by parts. $\displaystyle \int 5t\sqrt{t}\,dt=\int 5t^{3/2}\,dt=\dots$ Can you take it from here?
View Tag Cloud