f(x) = -2/(x-7)
We will take steps to find the tangent line to the graph of f at the point (42/3)
(a) Let (xf(x)) be a point on the graph of f with x=4. The slope of the (secant) line joining the two points (42/3) and (xf(x)) can be simplified to the form a/(x-7) where A is a constant. Find A .
(b) By considering the slope of the secant line as x approaches 4 , find the slope of the tangent line to the graph of f at the point (42/3)
(c) Find the equation of the tangent line to the graph of f at the point (42/3). Write your answer in the form y=mx+b.
No clue how to find A, first of all. I'm struggling with the rest obviously too or I wouldnt have posted it, but I'm trying to go one step at a time here. If you can help with all of it, that's great too though.