Evaluate the following limits, assuming all angles are in radian

a) lim x->0 (sin5x)/(sin6x)

b) lim x->0 (xsin6x)/(sin^2(9x))

c) lim x->0 (sin3x)/(9x-2tanx)

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- October 13th 2009, 05:26 PMkatekateLimits, radian angles
Evaluate the following limits, assuming all angles are in radian

a) lim x->0 (sin5x)/(sin6x)

b) lim x->0 (xsin6x)/(sin^2(9x))

c) lim x->0 (sin3x)/(9x-2tanx) - October 13th 2009, 05:32 PMartvandalay11
do you know l'hospital's rule?

- October 13th 2009, 05:36 PMkatekate
yeah i know l'hopital's rule...i definitely did not understand the second part you said but if i use l'hopital it should work

- October 13th 2009, 05:40 PMartvandalay11

lol that's just my signature and has nothing to do with you or this post, but let me do the first one and have you try the second one

is indeterminant, meaning you get if you try to plug into the expression, so we apply L'hospital's rule to get

do the same thing for the next - October 13th 2009, 05:55 PMkatekate
I can't get the second one but I get 3/5 for the third. I think im messing up the derivatives of both top and bottom.

**Edit:**never mind 3/5 is definitely wrong too - October 13th 2009, 06:15 PMartvandalay11
- October 13th 2009, 06:23 PMkatekate
great i got both of them now, i was squaring the 2 in the denominator when i shouldn't have been before in the third one. i didnt realize i had to use l'hopitals more than once, thanks a ton for everything