Fine the absolute minimum and absolute maximum of the function on the interval [0,6]
I did the minimum already, it's just the maximum.
f(x) = x
f'(x) = 1
g'(x) = 2x
Bottom is never 0, so do the quadratic formula on the top:
Which in the end gave me 4 and -4, which when plugging into F(x) gave me and
But plugging 6 in gave me
Is this valid?
In your case, we use the , and we find that the minima/maxima we get from that is -1/8 and 1/8 respectively. Now, to make sure these are global, and not just local, we compare them to the end points. At the end points we get 0 and 3/26 respectively. Now, -1/8 is LESS than 0, and 1/8 is MORE than 3/26. Therefore, we can confirm that the GLOBAL maxima is 1/8, and the GLOBAL minima is -1/8.