A gun fires a projectile toward a target that is 4.54 km distant at the same elevation as the gun. The gunnery officer notes that the projectile hit the target 27.5 s after firing

a) Find the angle of elevation of the gun barrel

b) Find the initial speed of the projectile

So we know

x= 4.54 km

t = 27.5 s

and V0= Vf

I cannot seem to figure out how to find the angle. It seems we are lacking a piece of information or either I am missing something simple. Any help appreciated. The instructor said I need two equation X & Y but I have no idea what is needed.