A gun fires a projectile toward a target that is 4.54 km distant at the same elevation as the gun. The gunnery officer notes that the projectile hit the target 27.5 s after firing
a) Find the angle of elevation of the gun barrel
b) Find the initial speed of the projectile
So we know
x= 4.54 km
t = 27.5 s
and V0= Vf
I cannot seem to figure out how to find the angle. It seems we are lacking a piece of information or either I am missing something simple. Any help appreciated. The instructor said I need two equation X & Y but I have no idea what is needed.