i need an explanation to the underlined answers pls (check attached picture) i got different answer for the first one i got : e^(lny+y)-e^y=y thnx
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Hello, Strange that no one replied to this... $\displaystyle [e^{x+y}]_0^{\ln(y)}=e^{\ln(y)+y}-e^{0+y}=e^{\ln(y)}e^y-e^y=ye^y-e^y=(y-1)e^y$ then they just performed an integration by parts
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