# Math Help - its a solved integration

1. ## its a solved integration

i need an explanation to the underlined answers pls (check attached picture)

i got different answer for the first one

i got : e^(lny+y)-e^y=y

thnx

2. Hello,

Strange that no one replied to this...

$[e^{x+y}]_0^{\ln(y)}=e^{\ln(y)+y}-e^{0+y}=e^{\ln(y)}e^y-e^y=ye^y-e^y=(y-1)e^y$

then they just performed an integration by parts