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Thread: its a solved integration

  1. October 13th 2009, 10:28 AM #1
    alex83
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    Exclamation its a solved integration

    i need an explanation to the underlined answers pls (check attached picture)

    i got different answer for the first one

    i got : e^(lny+y)-e^y=y


    thnx
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  2. November 7th 2009, 10:45 AM #2
    Moo
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    Hello,

    Strange that no one replied to this...

    [e^{x+y}]_0^{\ln(y)}=e^{\ln(y)+y}-e^{0+y}=e^{\ln(y)}e^y-e^y=ye^y-e^y=(y-1)e^y

    then they just performed an integration by parts
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