Originally Posted by

**ur5pointos2slo** I have posted a problem below and my attempt could someone please tell me if I am going wrong and where. Thanks

An automobile of mass 650 kg is acted on by a net force (F) given by F = 800 - 40.0t, where t is in seconds and F is in Newtons. At t=0, the velocity of the automobile is 5.00m/s.

a) Find the acceleration of the automobile at t=10.0s

800-40(t) / 650 = 400/650 = .615 m/s^2

b) Find the velocity of the automobile at t=10.0s

.615t = .615(10s) =6.15 m/s

c) Find the distance covered in this time.

x = (1/2)V*t

(1/2)(6.15)(10) = 30.75 m

d) At what time will the automobile be moving with a velocity of 15.0 m/s

V=at

t=V/a = 15/.615

t= 24 s