I have posted a problem below and my attempt could someone please tell me if I am going wrong and where. Thanks
An automobile of mass 650 kg is acted on by a net force (F) given by F = 800 - 40.0t, where t is in seconds and F is in Newtons. At t=0, the velocity of the automobile is 5.00m/s.
a) Find the acceleration of the automobile at t=10.0s
800-40(t) / 650 = 400/650 = .615 m/s^2
b) Find the velocity of the automobile at t=10.0s
.615t = .615(10s) =6.15 m/s
c) Find the distance covered in this time.
x = (1/2)V*t
(1/2)(6.15)(10) = 30.75 m
d) At what time will the automobile be moving with a velocity of 15.0 m/s
t=V/a = 15/.615
t= 24 s