prove that this series converges

**transgalactic** · October 13th 2009, 06:29 AM

$\sum \frac{e^{in\theta}}{\sqrt{n}}\\$
using Abel law
?

**chisigma** · October 13th 2009, 06:48 AM

The 'Abel's test' for the convergence of a series is described here...

Abel's Uniform Convergence Test -- from Wolfram MathWorld

In the case You have proposed we can observe that...

a) the sequence $e^{in\theta}$ is not 'monotonic decreasing'...

b) the series $\sum_{n} \frac{1}{\sqrt{n}}$ diverges...

It seems that the result of the Abel's test in this case is negative...

Kind regards

$\chi$ $\sigma$

**transgalactic** · October 14th 2009, 03:19 AM

i tried to go by that link to get a conclusion
1.
u_n(x) can be written u_n(x)=a_nf_n(x),

this expession is too weird for this law
$<br /> e^{in\theta}<br />$

i dont know how to apply it here
?

**chisigma** · October 14th 2009, 06:14 AM

The series you have proposed is the 'powers series'...

$\sum_{n=1}^{\infty} \frac{z^{n}}{\sqrt{n}}$ (1)

... computed in $z=e^{i\theta}$ , i.e. on the circle with center in $z=0$ and radious $1$ . It is easy to demonstrate that (1) converges for $|z|<1$ , i.e. for all points internal to that circle. A general criterion to extablish what happens on the circle of convergence doesn't exist. In this case we can say that the (1) diverges for $\theta=0$ ... for other points a detailed study is required...

Kind regards

$\chi$ $\sigma$

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