lim as x --> 0

$\displaystyle [sin^2 (2x)]/x^2 $

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- Oct 13th 2009, 06:26 AMfrozenflamesFind the limit as f(x) approaches 0
lim as x --> 0

$\displaystyle [sin^2 (2x)]/x^2 $ - Oct 13th 2009, 06:29 AMroshanhero
Use L'hospital rule

- Oct 13th 2009, 06:30 AMfrozenflames
- Oct 13th 2009, 06:39 AMroshanhero
Can u differentiate sin^2(x) and x^2

- Oct 13th 2009, 06:40 AMfrozenflames
- Oct 13th 2009, 06:48 AMroshanhero
yeap.............