integrate xSquareroot(x^2+2x+4) dx

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- Oct 13th 2009, 04:01 AMmikegar813Integration
integrate xSquareroot(x^2+2x+4) dx

- Oct 13th 2009, 04:33 AMHallsofIvy
Complete the square: x^2+ 2x+ 4= x^2+ 2x+ 1+ 3= (x+1)^2+ 3. First let u= x+1, then use a trig substitution.

This is the third question you have asked with any indication of what you have tried yourself. If you do not show your own work, I will not respond to any more questions. - Oct 13th 2009, 05:03 AMmikegar813
i just needed help starting them i will work them and post my work and answers. thanks.

- Oct 13th 2009, 05:14 AMmikegar813
if u=x+1

du=1 dx and when i substitute back in i get

integrate x Squareroot(u^2+3) dx

what do i do with the du since it doesn't match the x outside the squareroot? - Oct 14th 2009, 03:55 AMtonio
- Oct 14th 2009, 10:22 AMmikegar813
- Oct 14th 2009, 07:48 PMtonio