Show that z = x + iy is pure imaginary if and only if = -z
z = x +iy
- z = -x - iy = x - iy
x - iy = -x - iy
x = -x
Umm...yeah I don't know how this works. Can someone help?
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Sorry my mistake before editing.
From where you left off...
2x = 0.
Therefore x = 0
So the value of x (the real part) is 0 for z. So z must be imaginary if -z = z's conjugate.
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