If f(x)= sin²(3-x), then dy/dx(0)= ?
A. -2cos3
B. -2sin3cos3
C. 6cos3
D. 2sin3cos3
E. 6sin3cos3
This is a questions from my AP Calculus BC class, and I can't seem to get the correct answer. Any Thoughts?
Thanks!
Sure, start by differentiating $\displaystyle f(x)$.
It may be the case that you are confused because the problem contains two forms of notation.
Understand that $\displaystyle f'(x)=\frac{dy}{dx}$. The fact that this question would mix and match notation is a strong indication that your teachers are crap. But, don't let it get ya down.
So, you are asked to find $\displaystyle f'(0)$...