The straight line y = -x + 4 cuts the parabola with equation y = 16 - x^2 at the points A and B.

a) Find the coordinates of A and B.

Soo... since the line meets the parabola, I can solve by equating the equation of the line and the equation of the parabola/the equation of the gradient of the parabola. I ended up using the equation of the gradient.

So:

-x + 4 = -2x

x= -4

Subbing that into the equation of the parabola, I get y=0, so my first point is (-4, 0).

What is the exact method to find a second point?