Let f(x) = x^x.Give a convicing argument showing that f'(2)~ 6.773.
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Originally Posted by mathcalculushelp Let f(x) = x^x.Give a convicing argument showing that f'(2)~ 6.773. The first way would be to take the derivative using logarithmic differentation. Now taking the implicit derivative we get Now Or you could approximate it by using the difference quotient Now use very small values of h like or some other maybe smaller values.
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