A ball is tossed...
A ball is tossed straight up into the air from a bridge,and its height above the ground t seconds after it is thrown is
f(t)=-16t^2 + 108t + 82 feet.
a.How high above the ground is the bridge?
b. Write a function A(b) that gives the average velocity of the ball from t=0 to t=b seconds.Use the function to calculate the average velocity of the ball the first two seconds it is in the air.
Originally Posted by mathcalculushelp
A(b) = (f(0) - f(b)) / (0 - b)
plug values and simplify
Help me find t...?
-16t^2 + 180t + 48...??
I am getting stuck at finding t.
Iam not able to get the factors.If I use -b_+sq rt b^2 -4ac/2a then I get complicated ans.
How should I find t?
I think you need to find f(0) not f(t)=0
-16(0)^2 + 180(0) + 48 = f(0) , that's how high the ball is