# Direction of Vector

• Jan 27th 2007, 07:17 PM
c_323_h
Direction of Vector
Find the parametric equations for the line through (1, -1, 1) and parallel to the line x+2=0.5y=z-3

How do I obtain the direction of the line? Thanks
• Jan 27th 2007, 08:08 PM
Soroban
Hello, c_323_h!

Quote:

Find the parametric equations for the line through $(1,-1,1)$
and parallel to the line $x+2\;=\;\frac{1}{2}y\;=\;z-3$

How do I obtain the direction of the line?

They gave us the symmetric form of the line: . $\frac{x + 2}{1}\;=\;\frac{y}{2}\;=\;\frac{z-3}{1}$

The direction vector is: . $\langle1,\,2,\,1\rangle$ . . . the denominators.