Suppose f is a differentiable function of x and y, and g(u,v)=f(e^u+sinv, e^u+cosv) use the table of values to calculate gu(0,0) and gv(0,0).
at (0,0) f=3, g=6 fx=4 fx=8
I have no clue how to do this someone please help
Well I am not the same person who posted this thread. However, assuming this person was referring to problem #11 of section 11.5 of Essential Calculus-Early Transcendentals (James Stewart), then these are the correct values. If I am not mistaken, gu(0,0)=fx(1,2)e^u +fy(1,2)e^u =2e^0 +5e^0=7. gv(0,0) is not much different.
Oh, I see! (Although if you had gone on a 4-month quest for the table of values perhaps you would have have returned a different person!)
I don't think you're mistaken. Hopefully you can also see how Danny was holding one variable constant while differentiating with respect to the other.
Hopefully bringing this thread back to life.
I'm working on the exact same problem, and I have a handful of questions.
First of all, What exactly is G(v) and G(u)? I'm trying to follow along on this, and I'm understanding most other questions around it, but I'm at a loss for this one.
I understand transfering the initial equation down to x=e^u +sin(v) and y=e^u +cos(v),
but after that, I don't quite understand how to get to G(u)=Fx(Xu)+Fy(Yu)=e^(u)Fx + e^(u)Fy, or the same for G(v)
Any help is appreciated. Apologies for not fantastic formatting, just started up.
No one put the v in brackets - now it reads "function G of v" but you want to be saying "derivative with respect to v of g (which is a function of u and v)." So you say g_{v}, if you can format it so. (Maybe why you resorted to upper case g.) Or g_{v}(u,v), or for particular values 0 and 0 for u and v, g_{v}(0,0). In other words, dg/dv.
Just in case a picture helps...
... where (key in spoiler) ...
Spoiler:
Sorry I cluttered it a bit, because of the notation issue.
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Don't integrate - balloontegrate!
Balloon Calculus; standard integrals, derivatives and methods