Find the lim as x tends to 0+ of (ln x)^x.

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- Oct 9th 2009, 05:29 PMh2ospreyEvaluate a Limit
Find the lim as x tends to 0+ of (ln x)^x.

- Oct 9th 2009, 06:43 PMJose27
- Oct 9th 2009, 07:02 PMh2osprey
- Oct 9th 2009, 07:08 PMJose27
- Oct 9th 2009, 07:09 PMh2osprey
- Oct 9th 2009, 07:15 PMJose27
- Oct 9th 2009, 07:17 PMh2osprey
- Oct 9th 2009, 07:19 PMh2osprey
- Oct 9th 2009, 07:36 PMJose27
- Oct 9th 2009, 07:40 PMmr fantastic
- Oct 9th 2009, 07:56 PMJose27
. Now use L'Hopital.

Quote:

. So you should first consider which has the indeterminant form . Using l'Hopitals rule is an obvious thing to do.

- Oct 9th 2009, 08:46 PMNonCommAlg
i agree with

**Jose27**: does not exist because there is no right neighbourhood of which is a subset of the domain - Oct 9th 2009, 08:52 PMmr fantastic
- Oct 9th 2009, 09:00 PMJose27
The problem is, Wolfram Alpha is calculating the limit in the complex plane with the definition I first gave, but by what I understood the limit that was asked ignores this and uses only the fact negative numbers have odd roots (ie. we want the limit of a sequence, not the limit of the function)

- Oct 10th 2009, 12:44 AMh2osprey