So i can't figure out the following: f(x) = 2x^3 - 3x^2 - 72x + 6 ....for what values of x does this graph have a horizontal tangent...i think there are supposed to be two values
Follow Math Help Forum on Facebook and Google+
Originally Posted by frozenflames So i can't figure out the following: f(x) = 2x^3 - 3x^2 - 72x + 6 ....for what values of x does this graph have a horizontal tangent...i think there are supposed to be two values set $\displaystyle f'(x) = 0$ and solve for x.
quadratic... excellent i get 4 or -3... great, thanks
View Tag Cloud