If xsin(x)-y^2=xy-4, the value of dy/dx at the point (0,2) is ?
I don't know how to get the derivative, but if i got it I could solve it easily
For implicit differentiation :
1.When differentiating a function of x do it normally d(sinx)/dx =cos(x)
2. when differentiating a function of differentiate with respect to y and multiply by dy/dx : d(sin(y)/dx = cos(y) dy/dx
for your problem:
xsin(x)-y^2=xy-4
sin(x) + xcos(x) -2ydy/dx = y + xdy/dx
Now solve for dy/dx:
sin(x) +xcos(x) - y = (2y +x) dy/dx
[sin(x) +xcos(x) - y ]/(2y+x) = dy/dx