this is the question:
find the equation of the normal to the curve y=3+2x-x^2 which is parallel to the line 2y-x-3=0
please help me...i dont know how to do..
... gradient of tangent
so gradient of normal will be
have it equal to 1/2 . Do you know why ?
then solve for x , sub into the original equation to get y.
After that , make use the formula that i gave you in my post tp your other question to get the equation .
Have you tried doing what I suggested? What don't you understand? Where do you get stuck?