1) The number of yeast cells in a laboratory culture increases rapidly at first but levels off eventually. The population is modeled by the function below, where t is measured in hours. At time t = 0 the population is 10 cells and is increasing at a rate of 2 cells/hour.
a = ?
b = ?
According to this model, at what number of cell does the yeast population stabilize in the long run?
2) Suppose that a population of bacteria triples every hour and starts with 800 bacteria.
(a) Find an expression for the number n of bacteria after t hours.
f(t) = (800)3^t <- I did that already
f'(2.5) = ?
Yes, that's exactly what that means. You have and you know that f(0)= 10 and f'(0)= 2. f(0)= 10 gives you the equation . To use f'(0)= 2, you will need to differentiate f(x). You might find it simplest to write f(t) as and using the chain rule. Or else use the quotient rule.