solve the following limit,

limit when x approaches 0 from the positive direction

ln(4x)

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- Oct 8th 2009, 03:41 PMmath123456Limit of ln(4x) as x --> 0+
solve the following limit,

limit when x approaches 0 from the positive direction

ln(4x) - Oct 8th 2009, 03:52 PMKrizalid
diverges to $\displaystyle -\infty,$ do you see why?

- Oct 8th 2009, 03:54 PMmath123456derrivatives
can you show me how you got that answer

- Oct 8th 2009, 03:56 PMKrizalid
first note that $\displaystyle \ln4x=\ln4+\ln x$ so we'll worried about the $\displaystyle \ln x.$

now consider $\displaystyle x=\frac19,$ or $\displaystyle \frac1{99}$ and so on.

for small enough $\displaystyle x$ then using the fact that $\displaystyle \ln\frac1a=-\ln a$ yields the answer i gave.

take a moment and think it for a while.