# Limit of ln(4x) as x --> 0+

• Oct 8th 2009, 03:41 PM
math123456
Limit of ln(4x) as x --> 0+
solve the following limit,

limit when x approaches 0 from the positive direction

ln(4x)
• Oct 8th 2009, 03:52 PM
Krizalid
diverges to $-\infty,$ do you see why?
• Oct 8th 2009, 03:54 PM
math123456
derrivatives
can you show me how you got that answer
• Oct 8th 2009, 03:56 PM
Krizalid
first note that $\ln4x=\ln4+\ln x$ so we'll worried about the $\ln x.$

now consider $x=\frac19,$ or $\frac1{99}$ and so on.

for small enough $x$ then using the fact that $\ln\frac1a=-\ln a$ yields the answer i gave.

take a moment and think it for a while.