Use the squeeze theorem to solve the limit. limit when x approaches 0 x^4 cos (3/x)
Last edited by mr fantastic; Oct 8th 2009 at 04:29 PM. Reason: Changed post title
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Originally Posted by math123456 Use the squeeze theorem to solve the limit. limit when x approaches 0 x^4 cos (3/x) since $\displaystyle -1 \le \cos\left(\frac{3}{x}\right) \le 1$ and $\displaystyle x^4 \ge 0$ , $\displaystyle x^4(-1) \le x^4 \cos\left(\frac{3}{x}\right) \le x^4(1)$ squeeze it.
I am not sure what you mean by this. Can you help me solve it.
Originally Posted by skeeter since $\displaystyle -1 \le \cos\left(\frac{3}{x}\right) \le 1$ and $\displaystyle x^4 \ge 0$ , $\displaystyle x^4(-1) \le x^4 \cos\left(\frac{3}{x}\right) \le x^4(1)$ squeeze it. Originally Posted by math123456 I am not sure what you mean by this. Can you help me solve it. What is the limit of each side as x --> 0? Therefore ....
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