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Thread: find horizontal asymtote using limits

  1. October 7th 2009, 08:18 PM #1
    zweevu
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    find horizontal asymtote using limits

    f(x)= (8x^4 + 5x^3)/(16 + 7x^3 - x^4)
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  2. October 7th 2009, 09:43 PM #2
    mr fantastic
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    Quote Originally Posted by zweevu View Post
    f(x)= (8x^4 + 5x^3)/(16 + 7x^3 - x^4)
    Divide numerator and denominator by x^4 and then take the limit x --> oo. You get y = -8.
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