(t+2)*sin(t^2+4t+7) dt i don't know where to start
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Originally Posted by questionboy (t+2)*sin(t^2+4t+7) dt i don't know where to start $\displaystyle Let\ x=t^2+4t+7$ $\displaystyle dx = 2(t+2) \ or \ (t+2)dt=\frac{dx}{2}$ now substitute and solve
Got it thank you
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