i worked it out by differentiating f(y) and then g(y) to get:
5Ay^-6 + Be^y
but that's not hte right answer. am i differentiating wrong?
Find the equations of the tangent line, y1, and the normal line, y2 to the following curve at the given point P.
for y1 i got the derivative of y to get 4x^3 + 9e^x
and for y2 it should be the same thing since x is 0, i'm not sure what i'm doing wrong since both my answers are incorrect
Find a second-degree polynomial P such that the following conditions are met. P (6) = 8
P ' (6) = 8
P '' (6) = 4
this one is puzzling me as i'm not sure whre to start, should i start w/ functions that will work for original or should i start at the p"? not sure
I presume that you wrote f(y) as and then used the fact that the derivative of is and the derivative of is j. That would give - . Do you see the difference?
Yes, that is the correct derivative but what did you then do to find the tangent line? The tangent line at (0, 9) has slope and the normal line will have slope -1/9.Find the equations of the tangent line, y1, and the normal line, y2 to the following curve at the given point P.
for y1 i got the derivative of y to get 4x^3 + 9e^x
and for y2 it should be the same thing since x is 0, i'm not sure what i'm doing wrong since both my answers are incorrect
Start by writing your polynomial as , a general second degree polynomial. Find P' and P" from that. Setting P(6)= 8, P'(6)= 8, and P''(6)= 4 will give you three equations for A, B, and C.Find a second-degree polynomial P such that the following conditions are met. P (6) = 8
P ' (6) = 8
P '' (6) = 4
this one is puzzling me as i'm not sure whre to start, should i start w/ functions that will work for original or should i start at the p"? not sure
It might be even easier if you write the polynomial as which is also a perfectly good "general second degree polynomial".