Hi, How do I solve for the following: $\displaystyle d/dx [(0.1x + 0.4)log(0.1x + 0.4)]?$ I got the following answer but I think its wrong: $\displaystyle (1/ln2) + 0.1log(0.1x + 0.4).$ Can somebody help?
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what base log are you using ? at any rate I'll assume log base 2 from your answer first of all use the product rule: [.1x+.4] ' log(.1x+.4) + [.1x+.4] [log(.1x+.4)] ' = .1 log(.1x +.4) + {1/ln(2)}(.1x +.4)(.1/(.1x + .4) = .1 log(.1x +.4) + .1/ln(2)
Yes, its base 2. Thanks.
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