Hello I'm working on an impartial fraction problem
Long dividing we get
I don't know if i have to long divide again or do partial fraction exp...
Thanks
The division is incorrect:
[x^3 - x - 3]/[x^2 - x - 6] = x + 1+ [6x + 3] /[x^2 - x - 6] and now do an easy exercise of partial fractions on [6x + 3] /[x^2 - x - 6] = 3(2x + 1)/(x-3)(x+2)