Hello I'm working on an impartial fraction problem

$\displaystyle \int_0^1 \! \frac {x^3-x-3}{x^2-x-6} \, dx.$

Long dividing we get

$\displaystyle \int_0^1 \! x- \frac {x^2-7x-3}{x^2-x-6} \, dx.$

I don't know if i have to long divide again or do partial fraction exp...

Thanks